若a/2=b/3=c/4,则(3a—2b+5c)/(a+b+c)=

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若a/2=b/3=c/4,则(3a—2b+5c)/(a+b+c)=

若a/2=b/3=c/4,则(3a—2b+5c)/(a+b+c)=
若a/2=b/3=c/4,则(3a—2b+5c)/(a+b+c)=

若a/2=b/3=c/4,则(3a—2b+5c)/(a+b+c)=
a/2=b/3
3a=2b
a=c/2
b=3c/4
(3a—2b+5c)/(a+b+c)=
=5c/(a+b+c)=20/9

设:a/2=b/3=c/4=k
a=2k
b=3k
c=4k
(3a—2b+5c)/(a+b+c)=(6k-6k+20k)/(2k+3k+4k)=20k/9k=20/9

a/2=b/3=c/4=x
则a=2x,b=3x,c=4x
(3a—2b+5c)/(a+b+c)=(6x-6x+20x)/(2x+3x+4x)=20/9