作业帮设f(x)={|x-1|-2,|x|≤1,1/1+x2,|x|>1,则f[f(1/2)]等于设f(x)={|x-1|-2,|x|≤1,1/1+x2,|x|>1,则f[f(1/2)]等于
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/10 21:44:48
![设f(x)={|x-1|-2,|x|≤1,1/1+x2,|x|>1,则f[f(1/2)]等于设f(x)={|x-1|-2,|x|≤1,1/1+x2,|x|>1,则f[f(1/2)]等于](/uploads/image/z/2558637-45-7.jpg?t=%E8%AE%BEf%28x%29%3D%7B%7Cx-1%7C-2%2C%7Cx%7C%E2%89%A41%2C1%2F1%2Bx2%2C%7Cx%7C%3E1%2C%E5%88%99f%5Bf%281%2F2%29%5D%E7%AD%89%E4%BA%8E%E8%AE%BEf%28x%29%3D%7B%7Cx-1%7C-2%2C%7Cx%7C%E2%89%A41%2C1%2F1%2Bx2%2C%7Cx%7C%3E1%2C%E5%88%99f%5Bf%281%2F2%29%5D%E7%AD%89%E4%BA%8E)
设f(x)={|x-1|-2,|x|≤1,1/1+x2,|x|>1,则f[f(1/2)]等于设f(x)={|x-1|-2,|x|≤1,1/1+x2,|x|>1,则f[f(1/2)]等于
设f(x)={|x-1|-2,|x|≤1,1/1+x2,|x|>1,则f[f(1/2)]等于
设f(x)={|x-1|-2,|x|≤1,1/1+x2,|x|>1,则f[f(1/2)]等于
设f(x)={|x-1|-2,|x|≤1,1/1+x2,|x|>1,则f[f(1/2)]等于设f(x)={|x-1|-2,|x|≤1,1/1+x2,|x|>1,则f[f(1/2)]等于
如果|x|>1时,函数表达式为1与x的平方的和的倒数
那么,先算f(1/2)=-3/2
f(-3/2)=4/13
分段函数，画个图就好了，代两次，