若l3x-1l+(2y+1)²=0,求x-y分之2x²+3y²的值

若l3x-1l+(2y+1)²=0,求x-y分之2x²+3y²的值
若l3x-1l+(2y+1)²=0,求x-y分之2x²+3y²的值

若l3x-1l+(2y+1)²=0,求x-y分之2x²+3y²的值
l3x-1l+(2y+1)²=0
所以3x-1=0,2y+1=0
x=1/3,y=-1/2
所以原式=(2*1/9+3*1/4)/(1/3+1/2)=7/6

3x-1=0
x=1/3
2y+1=0
y=-1/2
2x^2+3y^2/x-y
=(2*1/9+3*1/4)/(1/3+1/2)
=(2/9+3/4)/(5/6)
=35/36 *6/5
=7/6

l3x-1l+(2y+1)²=0
且l3x-1l和(2y+1)²大于等于0 说明l3x-1l等于0且(2y+1)²等于0 说明3x-1和2y+1等于0说明x为三分之一，y为负二分之一

3x-1=0
x=1/3
2y+1=0
y=-1/2
x-2x^2/y+3y^2
=1/3-2*(1/9)/(-1/2)+3*1/4
=1/3-2/9*2+3/4
=1/3+4/9+3/4
=3/9+4/9+3/4
=7/9+3/4
=28/36+27/36
=55/36