作业帮根据1*2*3*4+4=25=5² 2*3*4*5+1=121=11² 3*4*5*6+1=361=19²,猜想(n+1)(n+2)(n+3)(n+4)+1=
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根据1*2*3*4+4=25=5² 2*3*4*5+1=121=11² 3*4*5*6+1=361=19²,猜想(n+1)(n+2)(n+3)(n+4)+1=
根据1*2*3*4+4=25=5² 2*3*4*5+1=121=11² 3*4*5*6+1=361=19²,猜想(n+1)(n+2)(n+3)(n+4)+1=
根据1*2*3*4+4=25=5² 2*3*4*5+1=121=11² 3*4*5*6+1=361=19²,猜想(n+1)(n+2)(n+3)(n+4)+1=
(n+1)(n+2)(n+3)(n+4)+1
=[(n+1)(n+4)+1]²
=(n²+5n+5)²
(n+1)(n+2)(n+3)(n+4)+1=(n+1)(n+4)[(n+1)+1][(n+4)-1]+1
=(n+1)(n+4)[(n+1)(n+4)+2]+1
=[(n+1)(n+4)]²+2(n+1)(n+4)+1
=[(n+1)(n+4)+1]²
=(n²+5n+5)²
(n+1)(N+2)(N+3)(N+4)+1={(N-3)N+1}²