(x^2+y)(x^2-Y)-(-x)^2*(-x^2) 已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少还有

来源：学生作业帮助网编辑：作业帮时间：2024/05/09 01:47:39

(x^2+y)(x^2-Y)-(-x)^2*(-x^2) 已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少还有
(x^2+y)(x^2-Y)-(-x)^2*(-x^2) 已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少
还有

(x^2+y)(x^2-Y)-(-x)^2*(-x^2) 已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少还有
(x^2+y)(x^2-Y)-(-x)^2*(-x^2)
=x^4-y²+x^4
=2x^4-y²

已知2^48-1可以被60到70之间的某两个整数整除,求这两个数是多少
2^48-1
=(2^24+1)(2^24-1)
=(2^24+1)(2^12+1)(2^12-1)
=(2^24+1)(2^12+1)(2^6+1)(2^6-1)
∴能被2^6+1及2^6-1
即65和63整除

(x^2+y)(x^2-y)-(-x)^2*(-x^2)
=x^4-y^2-x^2*(-x^2)
=x^4-y^2+x^4
=2x^4-y^2
2^48-1
=(2^24-1)(2^24+1)
=(2^12-1)(2^12+1)(2^24+1)
=(2^6-1)(2^6+1)(2^12+1)(2^24+1)
=63*65*(2^12+1)(2^24+1)
2^48-1可以被60到70之间的某两个整数整除，求这两个数是：63和65

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 化简y(x+y)+(x+y)(x-y)-x^2 因式分解x(x+y)(x-y)-x(x+y)^2 (x+y)(x-y)-(x-y)^2如题 (x+y)(x-y)-(x-y)^2 【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y) x^2(x-y)+(y-x) x(x-y)2-(y-x)3 计算:y-x分之x+y+x-y分之y-y-x分之2x-y 【(x-y)^2+(x+y)(x-y)】除以 2x [(x-y)²+(x+y)(x-y)]除以2x [2/3x-2/x+y(x+y/3x-x-y)]/x-y/x 化简：{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x 计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x 化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x [(x-y)^2-(x+2y)(x-2y)]/y 计算[2x^2-(x+y)(x-y)][(-x-y)(y-x)+2y^2] (x+y)^2(x-y)^2-(x-y)(x+y)(x^2+y^2)分解因式（x-y)(x-y)2(y-x) (x+2y-?）(x-2y+?)