分解因式(x+y)(x+y+2xy)+(xy+1)(xy-1)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 19:14:13
分解因式(x+y)(x+y+2xy)+(xy+1)(xy-1)

分解因式(x+y)(x+y+2xy)+(xy+1)(xy-1)
分解因式(x+y)(x+y+2xy)+(xy+1)(xy-1)

分解因式(x+y)(x+y+2xy)+(xy+1)(xy-1)
(x+y)(x+y+2xy)+(xy+1)(xy-1)
=(x+y)^2+2xy(x+y)+(xy+1)(xy-1)
=(x+y+xy+1)(x+y+xy-1) (十字相乘法分解)
=[(x+xy)+(y+1)](x+y+xy-1)
=[x(y+1)+(y+1)](x+y+xy-1)
=(x+1)(y+1)(x+y+xy-1).