已知,圆C:x2+y2-8x+12=0,直线l:ax+y+2a=0.(1)当a为何值时,直线l与圆C相切 (2)当直线l与圆C相交于A,B两点,且|AB|=2根号2时,求直线l的方程.你的答案不对 不好意思

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已知,圆C:x2+y2-8x+12=0,直线l:ax+y+2a=0.(1)当a为何值时,直线l与圆C相切 (2)当直线l与圆C相交于A,B两点,且|AB|=2根号2时,求直线l的方程.你的答案不对 不好意思

已知,圆C:x2+y2-8x+12=0,直线l:ax+y+2a=0.(1)当a为何值时,直线l与圆C相切 (2)当直线l与圆C相交于A,B两点,且|AB|=2根号2时,求直线l的方程.你的答案不对 不好意思
已知,圆C:x2+y2-8x+12=0,直线l:ax+y+2a=0.(1)当a为何值时,直线l与圆C相切 (2)当直线l与圆C相交于A,B两点,且|AB|=2根号2时,求直线l的方程.
你的答案不对 不好意思

已知,圆C:x2+y2-8x+12=0,直线l:ax+y+2a=0.(1)当a为何值时,直线l与圆C相切 (2)当直线l与圆C相交于A,B两点,且|AB|=2根号2时,求直线l的方程.你的答案不对 不好意思
x²-8x+16+y²=4
(x-4)²+y²=4
表示圆心为(4,0)半径为2的圆
根据题意
圆心到直线的距离为半径时相切
|4a+2a|/√(a²+1)=2
|3a|=√(a²+1)
9a²=a²+1
a²=1/8
a=±√2/4
(2)1/2|AB|=√2,半径为2
根据勾股定理,我们知道圆心到直线的距离为√2
所以有|4a+2a|/√(a²+1)=√2
36a²=2a²+2
17a²=1
a=±1/√17
直线为1/√17x+y+2/√17=0即x+√17y+2=0
或-1/√17x+y-2/√17=0即x-√17y+2=0
你说的哪一个不对?
你题目的数据准确吗?

这个题要自己想呀

我看楼上对的

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