已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an(n属於N+)证明数列{an+1-an}是等比数列?若数列{bn}满足(4^b1-1)(4^b2-1)……(4^bn-1)=(an+1)^bn,证明数列{bn}是等差数列?

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已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an(n属於N+)证明数列{an+1-an}是等比数列?若数列{bn}满足(4^b1-1)(4^b2-1)……(4^bn-1)=(an+1)^bn,证明数列{bn}是等差数列?

已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an(n属於N+)证明数列{an+1-an}是等比数列?若数列{bn}满足(4^b1-1)(4^b2-1)……(4^bn-1)=(an+1)^bn,证明数列{bn}是等差数列?
已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an(n属於N+)
证明数列{an+1-an}是等比数列?
若数列{bn}满足(4^b1-1)(4^b2-1)……(4^bn-1)=(an+1)^bn,证明数列{bn}是等差数列?

已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an(n属於N+)证明数列{an+1-an}是等比数列?若数列{bn}满足(4^b1-1)(4^b2-1)……(4^bn-1)=(an+1)^bn,证明数列{bn}是等差数列?
设bn=a(n+1)-an
an+2=3an+1-2an
a(n+2)=3a(n+1)-2an
a(n+2)-a(n+1)=2(a(n+1)-an)
b(n+1)=2b(n)
b1=a2-a1=2!=0
所以数列{an+1-an}是等比数列