约分(2n²-m)/(2mn-4n³)=?

约分(2n²-m)/(2mn-4n³)=?
约分(2n²-m)/(2mn-4n³)=?

约分(2n²-m)/(2mn-4n³)=?
∵(2n²-m)/(2mn-4n³)提取负号得：-【(2n²-m)/(4n³-2mn)】
又4n³-2mn = 2n·2n²-2n·m = 2n(2n²-m)
∴原式= -【（2n²-m）/2n(2n²-m)】
然后上下式的(2n²-m)可以消去
得到：-1/2n
∴等于-1/2n

(2n²-m)/(2mn-4n³)
=(2n²-m)/n(2m-4n^2)
=(2n²-m)/2n(m-2n^2)
=-1/2n