int y=1,x,*p,a[ ]={2,4,6,8,10}; p=&a[1]; for(x=0;x

int y=1,x,*p,a[ ]={2,4,6,8,10}; p=&a[1]; for(x=0;x
int y=1,x,*p,a[ ]={2,4,6,8,10}; p=&a[1]; for(x=0;x

int y=1,x,*p,a[ ]={2,4,6,8,10}; p=&a[1]; for(x=0;x
输出14
p=&a[1];相当于p[0] = a[1] = 4;
for(x=1;x<3;x++) y+=p[x];
注意x是从1开始,由于有x<3的条件,所以此循环进行2次,分别是x=1和x=2,所以y = p[1]+p[2] = 6+8 = 14