(3a+1)(2a-3)-6(a+2)(a-1)

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(3a+1)(2a-3)-6(a+2)(a-1)

(3a+1)(2a-3)-6(a+2)(a-1)
(3a+1)(2a-3)-6(a+2)(a-1)

(3a+1)(2a-3)-6(a+2)(a-1)
=(6a²-9a+2a-3)-6(a²-a+2a-2)
=6a²-7a-3-6a²-6a+12
=-13a+9

是这个式子等于0么?
6a^2-9a+2a-3=6a^2+12a-6a-12
-3+12=6a+7a
9=13a
a=9/13

很简单你还问?

(3a+1)(2a-3)-6(a+2)(a-1)=6a^2-7a-3-6(a^2+a-2)=6a^2-7a-3-6a^2-6a+12=-13a+9