32x-5-43y+4=5 (x+1)/5=y+2

初二上学期方程题 4x+y=5 5x+4y=63x-2y=1 2x+3y=13x-2y=7 7x+5y=32x+3y=17 2x-y=-4x+5y=6 2x+y=23x-6y=4 3x+2y=52x+y=73x-4y=53x+y=1x-2y=-1x+y=42x+3y=92x-3y=74x+5y=3x+y=20004x+6y=90003x+5y=113x-2y=42x+3y=215x-2y=5x+y=54x+3y=182x+3y=16x+4y=132x+3y=40x 化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1 y=|-x.x+4x+5| 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 5x-4y(y-x)=? 32x-5-43y+4=5 (x+1)/5=y+2 {x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0 求y=(5x-1)/(4x+2) (x 3x-2y=1 4x-5y 1/5x=4y改成比例式x:y():(). (x-y)/4+(x+y)/5=1/4 (x+y)/9-(x-y)/3=//2(x-y)/4+(x+y)/5=1/4(x+y)/9-(x-y)/3=//2 化简求值{(x=2y)(5x-2y)-(3x+2y)(3x-2y)]/4x,其中x=2,y=-1 x-y+5x-4x= ?x-y+5x-4x= ? 请解答方程组：（39）2x+y=5 (40)x+y=7 (41)2x+3y=12 (42)2x+y=3ax+3y=7 2x-y=8 3x+4y=17 3x-5y=11(43)3x+y=82 (44)3(x-1)=y+5 45 x/4+y/3=7 (46)x+y/3 +x-y/2=610x-11y=87 5(y-1)=3(x+5) 2/3x+y/2=14 3(x+y-)2(x-y)=28 4[2x+y]-5[2x-y]=32[2x+y]+10[2x-y]=39 ｛x-y=4 ｛5x-y=110 4x-y=－1 9y-x=110 （x-4y=-1 2x+y=16) (x-y=1 2x+y=5 ) （5x+3y)(3y-5x)-(4x-y)(4y+x)=