求不定积分:∫1/x(x^n+a)dx

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求不定积分:∫1/x(x^n+a)dx

求不定积分:∫1/x(x^n+a)dx
求不定积分:∫1/x(x^n+a)dx

求不定积分:∫1/x(x^n+a)dx
∫ 1/[x(x^n+a)] dx
= (1/a)∫ a/[x(x^n+a)] dx
= (1/a)∫ [(x^n+a)-x^n]/[x(x^n+a)] dx
= (1/a)∫ (x^n+a)/[x(x^n+a)] dx - (1/a)∫ x^n/[x(x^n+a)] dx
= (1/a)∫ 1/x dx - (1/a)∫ x^(n-1)/(x^n+a) dx
= (1/a)∫ 1/x dx - (1/a)∫ [x^(n-1+1)/(n-1+1)]/(x^n+a) dx
= (1/a)∫ 1/x dx - 1/(an) * ∫ d(x^n+a)/(x^n+a)
= (1/a)ln|x| - 1/(an) * ln|x^n+a| + C
= 1/(an) * ln|x^n/(x^n+a)| + C

∫1/x(x^n+a)dx=(1/na)ln[x^n/(x^n+a)]+c

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