化简：[tan(5/4)π+tan(5/12)π]/[1-tan(5/12)π]

化简：[tan(5/4)π+tan(5/12)π]/[1-tan(5/12)π] 化简：[tan（5π）/4+tan(5π)/12]/[1-tan(5π)/12] 求 tan^-1 (tan (5π/4) ) 在 -0.5π tan?=1/2 tan?=1/3 tan?=1/4 tan?=1/5 tan?=1/6 化简(tan5π/4+tan5π/12)/(1-tan5π/12)(tan 5π/4 + tan 5π/12)/(1-tan 5π/12) =(tan π/4 + tan π/6+π/4 )/(1-tan π/4*tan π/6+π/4 ) =tan(π/4 + π/6+π/4 )=tan(π/2+π/6) 请问我这样算错在哪呢?tan π/2不是无意义吗? 已知tan(A+B)=2/5,tan(B-π/4)=1/4,求tan(A+π/4已知tan(A+B)=2/5,tan(B-π/4)=1/4,求tan(A+π/4) tan(α+β)=3/5 tan(β-4/π)=1/4 则tan(α+4/π)等于多少 若tan(α+β)=3/5,tan(β-(π)/4)=1/4,则tan(α+(π)/4)=? tan(α+β)=3/5,tan(β-π/4)=1/4,则tan(α+π/4) tan(a+b)=2/5 tan(a+π/4)=3/22 求tan(b-π/4) 计算：1-tan（5π/12）tan(π/4） ------------------------------- tan(5π/12）+tan(π/4）那条横杠是分数线 已知tan(α+β)=2/5,tan(β-π/4)=1/4,求1+tanα/1-tanα的值大神们帮帮忙 化简tan(x+π/4)+tan(x+π/4) 化简tan(x+π/4)-tan(x-π/4) 化简tan(π/4+a)-tan(π/4-a)] tan(3π/5)和tan(-3π/5)大小 比较tan(-π/5)与tan(-3π)的大小 (tan(5π/8)*tan(π/8))为什么等于-1