cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(

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cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(

cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(

cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
=-1

注意到
cos1+cos179
=cos1+cos(180-1)
=cos1-cos1
=0
一般地,有
cosx+cos(180-x)=0
因此
cos1°+cos2°+cos3°....+cos180°
=(cos1+cos179)+(cos2+cos178)+...+(cos89+cos91)+cos90+cos180
=0+0+...+0+0+(-1)
=-1

_1

是求和吗?