已知,x^2+y^2-6x+2y+10=0,求(x+2y)^2(x-2y)^2-(x-2y)(x^2+4y^2)(x+2y)的值.

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已知,x^2+y^2-6x+2y+10=0,求(x+2y)^2(x-2y)^2-(x-2y)(x^2+4y^2)(x+2y)的值.

已知,x^2+y^2-6x+2y+10=0,求(x+2y)^2(x-2y)^2-(x-2y)(x^2+4y^2)(x+2y)的值.
已知,x^2+y^2-6x+2y+10=0,求(x+2y)^2(x-2y)^2-(x-2y)(x^2+4y^2)(x+2y)的值.

已知,x^2+y^2-6x+2y+10=0,求(x+2y)^2(x-2y)^2-(x-2y)(x^2+4y^2)(x+2y)的值.
x^2+y^2-6x+2y+10=(x-3)^2+(y+1)^2=0
在实数范围内,显然,
x=3
y=-1
(x+2y)^2(x-2y)^2-(x-2y)(x^2+4y^2)(x+2y)
=[(x+2y)(x-2y)]^2 - [(x^2+4y^2)(x^2-4y^2)]
=(x^2-4y^2)(-8y^2)
=(3*3-4)*(-8)
=-40