x-y+(37/12)=3 1.1=0.8y+0.75x 该方程组怎么解?x=?y=?

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x-y+(37/12)=3 1.1=0.8y+0.75x 该方程组怎么解?x=?y=?

x-y+(37/12)=3 1.1=0.8y+0.75x 该方程组怎么解?x=?y=?
x-y+(37/12)=3 1.1=0.8y+0.75x 该方程组怎么解?x=?y=?

x-y+(37/12)=3 1.1=0.8y+0.75x 该方程组怎么解?x=?y=?
由X-Y+(37/12)=3 1.1=0.8y+0.75x 得Y=X+1/12;
把Y=X+1/12代入1.1=0.8y+0.75x
11/10=4/5(X+1/12)+3/4*X
11/10-4/5*1/12=(4/5+3/4)*X
11/10-1/15=31/20*X
(66-4)/60=93/60*x
x=62/93
x=2/3
把x=2/3代入Y=X+1/12得Y=3/4
所以X=2/3 Y=3/4

x-y+(37/12)=3 1.1,8x-8y+74/3=248.8
0.8y+0.75x =3 1.1,8y+7.5x=311
x=5598/155,y=3493/1860

x=-34/93, y=213/124