化简[sin(θ-5π)cot(π/2-θ)cos(8π-θ)]/[tan(3π-θ)tan(θ-3/2π)sin(-θ-4π)]

化简cos(α-π)cot(5π-α)/tan(2π-α)sin(-2π-α) 化简cos(a-π)cot(5π-a)/sin(-2π-a) 化简[sin(θ-5π)cot(π/2-θ)cos(8π-θ)]/[tan(3π-θ)tan(θ-3/2π)sin(-θ-4π)] sin(θ -5π)/tan(3π-θ)*cot(π/2-θ)/tan(θ -3/2π)*cos(8π-θ)/sin(-θ-4π)化简 cot(π+θ)=2,则(3sinθ-cosθ)/(sinθ+cosθ)=? 化简：sin（3π +a ) cot (- π +a )=? 化简cot(-α-π)·sin(-π-α) 化简sin(-11π/3)+cos(12π/5)tan2π-sec13π/5cot(-5π/2) 化简[sin(π-α)tan(5π/2+α)]/[cos(2π-α)cot(π/2-α)]分后给 化简cos(a-π)cot(5π-a)/sin(-2π-a)答案是-cota的平方, 化简:sin(a-π)cot(a-2π)/cos(a-π)tan(a-2π) 已知sinθ+cosθ=1/5,θ∈(0,π),求cotθ? 化简：2sin^2（19/4π)+tan^2(37/4π)*cot(-9/4π) 化简sin(2π-a)cot(π+a)/cos(π-a)的结果为 (sin(-a-π)-tan(-a)+cot(π/2+a))/((tana-π)+cos(π-a)+sin((3π)/2+a)) 化简 化简cos(π-a)sin(a-2π)/sin(-a-π)cot(π+a)怎么做,急 化简:cos^2θcotθ+sin^2θtanθ+2cosθsinθ 化简[cos（α-π）*cot（5π-α）]/[sin（-2π-α）]②sine*根号下（1+cot²e）（e为第三象限角）